3.596 \(\int \frac{(d+e x)^3 (a+c x^2)}{(f+g x)^{3/2}} \, dx\)

Optimal. Leaf size=238 \[ \frac{2 e (f+g x)^{5/2} \left (a e^2 g^2+c \left (3 d^2 g^2-12 d e f g+10 e^2 f^2\right )\right )}{5 g^6}-\frac{2 (f+g x)^{3/2} (e f-d g) \left (3 a e^2 g^2+c \left (d^2 g^2-8 d e f g+10 e^2 f^2\right )\right )}{3 g^6}+\frac{2 \left (a g^2+c f^2\right ) (e f-d g)^3}{g^6 \sqrt{f+g x}}+\frac{2 \sqrt{f+g x} (e f-d g)^2 \left (3 a e g^2+c f (5 e f-2 d g)\right )}{g^6}-\frac{2 c e^2 (f+g x)^{7/2} (5 e f-3 d g)}{7 g^6}+\frac{2 c e^3 (f+g x)^{9/2}}{9 g^6} \]

[Out]

(2*(e*f - d*g)^3*(c*f^2 + a*g^2))/(g^6*Sqrt[f + g*x]) + (2*(e*f - d*g)^2*(3*a*e*g^2 + c*f*(5*e*f - 2*d*g))*Sqr
t[f + g*x])/g^6 - (2*(e*f - d*g)*(3*a*e^2*g^2 + c*(10*e^2*f^2 - 8*d*e*f*g + d^2*g^2))*(f + g*x)^(3/2))/(3*g^6)
+ (2*e*(a*e^2*g^2 + c*(10*e^2*f^2 - 12*d*e*f*g + 3*d^2*g^2))*(f + g*x)^(5/2))/(5*g^6) - (2*c*e^2*(5*e*f - 3*d
*g)*(f + g*x)^(7/2))/(7*g^6) + (2*c*e^3*(f + g*x)^(9/2))/(9*g^6)

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Rubi [A]  time = 0.268299, antiderivative size = 238, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.083, Rules used = {898, 1261} \[ \frac{2 e (f+g x)^{5/2} \left (a e^2 g^2+c \left (3 d^2 g^2-12 d e f g+10 e^2 f^2\right )\right )}{5 g^6}-\frac{2 (f+g x)^{3/2} (e f-d g) \left (3 a e^2 g^2+c \left (d^2 g^2-8 d e f g+10 e^2 f^2\right )\right )}{3 g^6}+\frac{2 \left (a g^2+c f^2\right ) (e f-d g)^3}{g^6 \sqrt{f+g x}}+\frac{2 \sqrt{f+g x} (e f-d g)^2 \left (3 a e g^2+c f (5 e f-2 d g)\right )}{g^6}-\frac{2 c e^2 (f+g x)^{7/2} (5 e f-3 d g)}{7 g^6}+\frac{2 c e^3 (f+g x)^{9/2}}{9 g^6} \]

Antiderivative was successfully verified.

[In]

Int[((d + e*x)^3*(a + c*x^2))/(f + g*x)^(3/2),x]

[Out]

(2*(e*f - d*g)^3*(c*f^2 + a*g^2))/(g^6*Sqrt[f + g*x]) + (2*(e*f - d*g)^2*(3*a*e*g^2 + c*f*(5*e*f - 2*d*g))*Sqr
t[f + g*x])/g^6 - (2*(e*f - d*g)*(3*a*e^2*g^2 + c*(10*e^2*f^2 - 8*d*e*f*g + d^2*g^2))*(f + g*x)^(3/2))/(3*g^6)
+ (2*e*(a*e^2*g^2 + c*(10*e^2*f^2 - 12*d*e*f*g + 3*d^2*g^2))*(f + g*x)^(5/2))/(5*g^6) - (2*c*e^2*(5*e*f - 3*d
*g)*(f + g*x)^(7/2))/(7*g^6) + (2*c*e^3*(f + g*x)^(9/2))/(9*g^6)

Rule 898

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))^(n_)*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> With[{q = De
nominator[m]}, Dist[q/e, Subst[Int[x^(q*(m + 1) - 1)*((e*f - d*g)/e + (g*x^q)/e)^n*((c*d^2 + a*e^2)/e^2 - (2*c
*d*x^q)/e^2 + (c*x^(2*q))/e^2)^p, x], x, (d + e*x)^(1/q)], x]] /; FreeQ[{a, c, d, e, f, g}, x] && NeQ[e*f - d*
g, 0] && NeQ[c*d^2 + a*e^2, 0] && IntegersQ[n, p] && FractionQ[m]

Rule 1261

Int[((f_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_.), x_Symbol] :> In
t[ExpandIntegrand[(f*x)^m*(d + e*x^2)^q*(a + b*x^2 + c*x^4)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, q}, x] &&
NeQ[b^2 - 4*a*c, 0] && IGtQ[p, 0] && IGtQ[q, -2]

Rubi steps

\begin{align*} \int \frac{(d+e x)^3 \left (a+c x^2\right )}{(f+g x)^{3/2}} \, dx &=\frac{2 \operatorname{Subst}\left (\int \frac{\left (\frac{-e f+d g}{g}+\frac{e x^2}{g}\right )^3 \left (\frac{c f^2+a g^2}{g^2}-\frac{2 c f x^2}{g^2}+\frac{c x^4}{g^2}\right )}{x^2} \, dx,x,\sqrt{f+g x}\right )}{g}\\ &=\frac{2 \operatorname{Subst}\left (\int \left (\frac{(e f-d g)^2 \left (3 a e g^2+c f (5 e f-2 d g)\right )}{g^5}+\frac{(-e f+d g)^3 \left (c f^2+a g^2\right )}{g^5 x^2}+\frac{(e f-d g) \left (-3 a e^2 g^2-c \left (10 e^2 f^2-8 d e f g+d^2 g^2\right )\right ) x^2}{g^5}+\frac{e \left (a e^2 g^2+c \left (10 e^2 f^2-12 d e f g+3 d^2 g^2\right )\right ) x^4}{g^5}-\frac{c e^2 (5 e f-3 d g) x^6}{g^5}+\frac{c e^3 x^8}{g^5}\right ) \, dx,x,\sqrt{f+g x}\right )}{g}\\ &=\frac{2 (e f-d g)^3 \left (c f^2+a g^2\right )}{g^6 \sqrt{f+g x}}+\frac{2 (e f-d g)^2 \left (3 a e g^2+c f (5 e f-2 d g)\right ) \sqrt{f+g x}}{g^6}-\frac{2 (e f-d g) \left (3 a e^2 g^2+c \left (10 e^2 f^2-8 d e f g+d^2 g^2\right )\right ) (f+g x)^{3/2}}{3 g^6}+\frac{2 e \left (a e^2 g^2+c \left (10 e^2 f^2-12 d e f g+3 d^2 g^2\right )\right ) (f+g x)^{5/2}}{5 g^6}-\frac{2 c e^2 (5 e f-3 d g) (f+g x)^{7/2}}{7 g^6}+\frac{2 c e^3 (f+g x)^{9/2}}{9 g^6}\\ \end{align*}

Mathematica [A]  time = 0.246201, size = 207, normalized size = 0.87 \[ \frac{2 \left (63 e (f+g x)^3 \left (a e^2 g^2+c \left (3 d^2 g^2-12 d e f g+10 e^2 f^2\right )\right )-105 (f+g x)^2 (e f-d g) \left (3 a e^2 g^2+c \left (d^2 g^2-8 d e f g+10 e^2 f^2\right )\right )+315 \left (a g^2+c f^2\right ) (e f-d g)^3+315 (f+g x) (e f-d g)^2 \left (3 a e g^2+c f (5 e f-2 d g)\right )-45 c e^2 (f+g x)^4 (5 e f-3 d g)+35 c e^3 (f+g x)^5\right )}{315 g^6 \sqrt{f+g x}} \]

Antiderivative was successfully verified.

[In]

Integrate[((d + e*x)^3*(a + c*x^2))/(f + g*x)^(3/2),x]

[Out]

(2*(315*(e*f - d*g)^3*(c*f^2 + a*g^2) + 315*(e*f - d*g)^2*(3*a*e*g^2 + c*f*(5*e*f - 2*d*g))*(f + g*x) - 105*(e
*f - d*g)*(3*a*e^2*g^2 + c*(10*e^2*f^2 - 8*d*e*f*g + d^2*g^2))*(f + g*x)^2 + 63*e*(a*e^2*g^2 + c*(10*e^2*f^2 -
12*d*e*f*g + 3*d^2*g^2))*(f + g*x)^3 - 45*c*e^2*(5*e*f - 3*d*g)*(f + g*x)^4 + 35*c*e^3*(f + g*x)^5))/(315*g^6
*Sqrt[f + g*x])

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Maple [A]  time = 0.049, size = 365, normalized size = 1.5 \begin{align*} -{\frac{-70\,{e}^{3}c{x}^{5}{g}^{5}-270\,cd{e}^{2}{g}^{5}{x}^{4}+100\,c{e}^{3}f{g}^{4}{x}^{4}-126\,a{e}^{3}{g}^{5}{x}^{3}-378\,c{d}^{2}e{g}^{5}{x}^{3}+432\,cd{e}^{2}f{g}^{4}{x}^{3}-160\,c{e}^{3}{f}^{2}{g}^{3}{x}^{3}-630\,ad{e}^{2}{g}^{5}{x}^{2}+252\,a{e}^{3}f{g}^{4}{x}^{2}-210\,c{d}^{3}{g}^{5}{x}^{2}+756\,c{d}^{2}ef{g}^{4}{x}^{2}-864\,cd{e}^{2}{f}^{2}{g}^{3}{x}^{2}+320\,c{e}^{3}{f}^{3}{g}^{2}{x}^{2}-1890\,a{d}^{2}e{g}^{5}x+2520\,ad{e}^{2}f{g}^{4}x-1008\,a{e}^{3}{f}^{2}{g}^{3}x+840\,c{d}^{3}f{g}^{4}x-3024\,c{d}^{2}e{f}^{2}{g}^{3}x+3456\,cd{e}^{2}{f}^{3}{g}^{2}x-1280\,c{e}^{3}{f}^{4}gx+630\,{d}^{3}a{g}^{5}-3780\,a{d}^{2}ef{g}^{4}+5040\,ad{e}^{2}{f}^{2}{g}^{3}-2016\,a{e}^{3}{f}^{3}{g}^{2}+1680\,c{d}^{3}{f}^{2}{g}^{3}-6048\,c{d}^{2}e{f}^{3}{g}^{2}+6912\,cd{e}^{2}{f}^{4}g-2560\,c{e}^{3}{f}^{5}}{315\,{g}^{6}}{\frac{1}{\sqrt{gx+f}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x+d)^3*(c*x^2+a)/(g*x+f)^(3/2),x)

[Out]

-2/315/(g*x+f)^(1/2)*(-35*c*e^3*g^5*x^5-135*c*d*e^2*g^5*x^4+50*c*e^3*f*g^4*x^4-63*a*e^3*g^5*x^3-189*c*d^2*e*g^
5*x^3+216*c*d*e^2*f*g^4*x^3-80*c*e^3*f^2*g^3*x^3-315*a*d*e^2*g^5*x^2+126*a*e^3*f*g^4*x^2-105*c*d^3*g^5*x^2+378
*c*d^2*e*f*g^4*x^2-432*c*d*e^2*f^2*g^3*x^2+160*c*e^3*f^3*g^2*x^2-945*a*d^2*e*g^5*x+1260*a*d*e^2*f*g^4*x-504*a*
e^3*f^2*g^3*x+420*c*d^3*f*g^4*x-1512*c*d^2*e*f^2*g^3*x+1728*c*d*e^2*f^3*g^2*x-640*c*e^3*f^4*g*x+315*a*d^3*g^5-
1890*a*d^2*e*f*g^4+2520*a*d*e^2*f^2*g^3-1008*a*e^3*f^3*g^2+840*c*d^3*f^2*g^3-3024*c*d^2*e*f^3*g^2+3456*c*d*e^2
*f^4*g-1280*c*e^3*f^5)/g^6

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Maxima [A]  time = 1.03147, size = 451, normalized size = 1.89 \begin{align*} \frac{2 \,{\left (\frac{35 \,{\left (g x + f\right )}^{\frac{9}{2}} c e^{3} - 45 \,{\left (5 \, c e^{3} f - 3 \, c d e^{2} g\right )}{\left (g x + f\right )}^{\frac{7}{2}} + 63 \,{\left (10 \, c e^{3} f^{2} - 12 \, c d e^{2} f g +{\left (3 \, c d^{2} e + a e^{3}\right )} g^{2}\right )}{\left (g x + f\right )}^{\frac{5}{2}} - 105 \,{\left (10 \, c e^{3} f^{3} - 18 \, c d e^{2} f^{2} g + 3 \,{\left (3 \, c d^{2} e + a e^{3}\right )} f g^{2} -{\left (c d^{3} + 3 \, a d e^{2}\right )} g^{3}\right )}{\left (g x + f\right )}^{\frac{3}{2}} + 315 \,{\left (5 \, c e^{3} f^{4} - 12 \, c d e^{2} f^{3} g + 3 \, a d^{2} e g^{4} + 3 \,{\left (3 \, c d^{2} e + a e^{3}\right )} f^{2} g^{2} - 2 \,{\left (c d^{3} + 3 \, a d e^{2}\right )} f g^{3}\right )} \sqrt{g x + f}}{g^{5}} + \frac{315 \,{\left (c e^{3} f^{5} - 3 \, c d e^{2} f^{4} g + 3 \, a d^{2} e f g^{4} - a d^{3} g^{5} +{\left (3 \, c d^{2} e + a e^{3}\right )} f^{3} g^{2} -{\left (c d^{3} + 3 \, a d e^{2}\right )} f^{2} g^{3}\right )}}{\sqrt{g x + f} g^{5}}\right )}}{315 \, g} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^3*(c*x^2+a)/(g*x+f)^(3/2),x, algorithm="maxima")

[Out]

2/315*((35*(g*x + f)^(9/2)*c*e^3 - 45*(5*c*e^3*f - 3*c*d*e^2*g)*(g*x + f)^(7/2) + 63*(10*c*e^3*f^2 - 12*c*d*e^
2*f*g + (3*c*d^2*e + a*e^3)*g^2)*(g*x + f)^(5/2) - 105*(10*c*e^3*f^3 - 18*c*d*e^2*f^2*g + 3*(3*c*d^2*e + a*e^3
)*f*g^2 - (c*d^3 + 3*a*d*e^2)*g^3)*(g*x + f)^(3/2) + 315*(5*c*e^3*f^4 - 12*c*d*e^2*f^3*g + 3*a*d^2*e*g^4 + 3*(
3*c*d^2*e + a*e^3)*f^2*g^2 - 2*(c*d^3 + 3*a*d*e^2)*f*g^3)*sqrt(g*x + f))/g^5 + 315*(c*e^3*f^5 - 3*c*d*e^2*f^4*
g + 3*a*d^2*e*f*g^4 - a*d^3*g^5 + (3*c*d^2*e + a*e^3)*f^3*g^2 - (c*d^3 + 3*a*d*e^2)*f^2*g^3)/(sqrt(g*x + f)*g^
5))/g

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Fricas [A]  time = 1.75808, size = 749, normalized size = 3.15 \begin{align*} \frac{2 \,{\left (35 \, c e^{3} g^{5} x^{5} + 1280 \, c e^{3} f^{5} - 3456 \, c d e^{2} f^{4} g + 1890 \, a d^{2} e f g^{4} - 315 \, a d^{3} g^{5} + 1008 \,{\left (3 \, c d^{2} e + a e^{3}\right )} f^{3} g^{2} - 840 \,{\left (c d^{3} + 3 \, a d e^{2}\right )} f^{2} g^{3} - 5 \,{\left (10 \, c e^{3} f g^{4} - 27 \, c d e^{2} g^{5}\right )} x^{4} +{\left (80 \, c e^{3} f^{2} g^{3} - 216 \, c d e^{2} f g^{4} + 63 \,{\left (3 \, c d^{2} e + a e^{3}\right )} g^{5}\right )} x^{3} -{\left (160 \, c e^{3} f^{3} g^{2} - 432 \, c d e^{2} f^{2} g^{3} + 126 \,{\left (3 \, c d^{2} e + a e^{3}\right )} f g^{4} - 105 \,{\left (c d^{3} + 3 \, a d e^{2}\right )} g^{5}\right )} x^{2} +{\left (640 \, c e^{3} f^{4} g - 1728 \, c d e^{2} f^{3} g^{2} + 945 \, a d^{2} e g^{5} + 504 \,{\left (3 \, c d^{2} e + a e^{3}\right )} f^{2} g^{3} - 420 \,{\left (c d^{3} + 3 \, a d e^{2}\right )} f g^{4}\right )} x\right )} \sqrt{g x + f}}{315 \,{\left (g^{7} x + f g^{6}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^3*(c*x^2+a)/(g*x+f)^(3/2),x, algorithm="fricas")

[Out]

2/315*(35*c*e^3*g^5*x^5 + 1280*c*e^3*f^5 - 3456*c*d*e^2*f^4*g + 1890*a*d^2*e*f*g^4 - 315*a*d^3*g^5 + 1008*(3*c
*d^2*e + a*e^3)*f^3*g^2 - 840*(c*d^3 + 3*a*d*e^2)*f^2*g^3 - 5*(10*c*e^3*f*g^4 - 27*c*d*e^2*g^5)*x^4 + (80*c*e^
3*f^2*g^3 - 216*c*d*e^2*f*g^4 + 63*(3*c*d^2*e + a*e^3)*g^5)*x^3 - (160*c*e^3*f^3*g^2 - 432*c*d*e^2*f^2*g^3 + 1
26*(3*c*d^2*e + a*e^3)*f*g^4 - 105*(c*d^3 + 3*a*d*e^2)*g^5)*x^2 + (640*c*e^3*f^4*g - 1728*c*d*e^2*f^3*g^2 + 94
5*a*d^2*e*g^5 + 504*(3*c*d^2*e + a*e^3)*f^2*g^3 - 420*(c*d^3 + 3*a*d*e^2)*f*g^4)*x)*sqrt(g*x + f)/(g^7*x + f*g
^6)

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Sympy [A]  time = 56.0701, size = 328, normalized size = 1.38 \begin{align*} \frac{2 c e^{3} \left (f + g x\right )^{\frac{9}{2}}}{9 g^{6}} + \frac{\left (f + g x\right )^{\frac{7}{2}} \left (6 c d e^{2} g - 10 c e^{3} f\right )}{7 g^{6}} + \frac{\left (f + g x\right )^{\frac{5}{2}} \left (2 a e^{3} g^{2} + 6 c d^{2} e g^{2} - 24 c d e^{2} f g + 20 c e^{3} f^{2}\right )}{5 g^{6}} + \frac{\left (f + g x\right )^{\frac{3}{2}} \left (6 a d e^{2} g^{3} - 6 a e^{3} f g^{2} + 2 c d^{3} g^{3} - 18 c d^{2} e f g^{2} + 36 c d e^{2} f^{2} g - 20 c e^{3} f^{3}\right )}{3 g^{6}} + \frac{\sqrt{f + g x} \left (6 a d^{2} e g^{4} - 12 a d e^{2} f g^{3} + 6 a e^{3} f^{2} g^{2} - 4 c d^{3} f g^{3} + 18 c d^{2} e f^{2} g^{2} - 24 c d e^{2} f^{3} g + 10 c e^{3} f^{4}\right )}{g^{6}} - \frac{2 \left (a g^{2} + c f^{2}\right ) \left (d g - e f\right )^{3}}{g^{6} \sqrt{f + g x}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)**3*(c*x**2+a)/(g*x+f)**(3/2),x)

[Out]

2*c*e**3*(f + g*x)**(9/2)/(9*g**6) + (f + g*x)**(7/2)*(6*c*d*e**2*g - 10*c*e**3*f)/(7*g**6) + (f + g*x)**(5/2)
*(2*a*e**3*g**2 + 6*c*d**2*e*g**2 - 24*c*d*e**2*f*g + 20*c*e**3*f**2)/(5*g**6) + (f + g*x)**(3/2)*(6*a*d*e**2*
g**3 - 6*a*e**3*f*g**2 + 2*c*d**3*g**3 - 18*c*d**2*e*f*g**2 + 36*c*d*e**2*f**2*g - 20*c*e**3*f**3)/(3*g**6) +
sqrt(f + g*x)*(6*a*d**2*e*g**4 - 12*a*d*e**2*f*g**3 + 6*a*e**3*f**2*g**2 - 4*c*d**3*f*g**3 + 18*c*d**2*e*f**2*
g**2 - 24*c*d*e**2*f**3*g + 10*c*e**3*f**4)/g**6 - 2*(a*g**2 + c*f**2)*(d*g - e*f)**3/(g**6*sqrt(f + g*x))

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Giac [B]  time = 1.17236, size = 612, normalized size = 2.57 \begin{align*} -\frac{2 \,{\left (c d^{3} f^{2} g^{3} + a d^{3} g^{5} - 3 \, c d^{2} f^{3} g^{2} e - 3 \, a d^{2} f g^{4} e + 3 \, c d f^{4} g e^{2} + 3 \, a d f^{2} g^{3} e^{2} - c f^{5} e^{3} - a f^{3} g^{2} e^{3}\right )}}{\sqrt{g x + f} g^{6}} + \frac{2 \,{\left (105 \,{\left (g x + f\right )}^{\frac{3}{2}} c d^{3} g^{51} - 630 \, \sqrt{g x + f} c d^{3} f g^{51} + 189 \,{\left (g x + f\right )}^{\frac{5}{2}} c d^{2} g^{50} e - 945 \,{\left (g x + f\right )}^{\frac{3}{2}} c d^{2} f g^{50} e + 2835 \, \sqrt{g x + f} c d^{2} f^{2} g^{50} e + 945 \, \sqrt{g x + f} a d^{2} g^{52} e + 135 \,{\left (g x + f\right )}^{\frac{7}{2}} c d g^{49} e^{2} - 756 \,{\left (g x + f\right )}^{\frac{5}{2}} c d f g^{49} e^{2} + 1890 \,{\left (g x + f\right )}^{\frac{3}{2}} c d f^{2} g^{49} e^{2} - 3780 \, \sqrt{g x + f} c d f^{3} g^{49} e^{2} + 315 \,{\left (g x + f\right )}^{\frac{3}{2}} a d g^{51} e^{2} - 1890 \, \sqrt{g x + f} a d f g^{51} e^{2} + 35 \,{\left (g x + f\right )}^{\frac{9}{2}} c g^{48} e^{3} - 225 \,{\left (g x + f\right )}^{\frac{7}{2}} c f g^{48} e^{3} + 630 \,{\left (g x + f\right )}^{\frac{5}{2}} c f^{2} g^{48} e^{3} - 1050 \,{\left (g x + f\right )}^{\frac{3}{2}} c f^{3} g^{48} e^{3} + 1575 \, \sqrt{g x + f} c f^{4} g^{48} e^{3} + 63 \,{\left (g x + f\right )}^{\frac{5}{2}} a g^{50} e^{3} - 315 \,{\left (g x + f\right )}^{\frac{3}{2}} a f g^{50} e^{3} + 945 \, \sqrt{g x + f} a f^{2} g^{50} e^{3}\right )}}{315 \, g^{54}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^3*(c*x^2+a)/(g*x+f)^(3/2),x, algorithm="giac")

[Out]

-2*(c*d^3*f^2*g^3 + a*d^3*g^5 - 3*c*d^2*f^3*g^2*e - 3*a*d^2*f*g^4*e + 3*c*d*f^4*g*e^2 + 3*a*d*f^2*g^3*e^2 - c*
f^5*e^3 - a*f^3*g^2*e^3)/(sqrt(g*x + f)*g^6) + 2/315*(105*(g*x + f)^(3/2)*c*d^3*g^51 - 630*sqrt(g*x + f)*c*d^3
*f*g^51 + 189*(g*x + f)^(5/2)*c*d^2*g^50*e - 945*(g*x + f)^(3/2)*c*d^2*f*g^50*e + 2835*sqrt(g*x + f)*c*d^2*f^2
*g^50*e + 945*sqrt(g*x + f)*a*d^2*g^52*e + 135*(g*x + f)^(7/2)*c*d*g^49*e^2 - 756*(g*x + f)^(5/2)*c*d*f*g^49*e
^2 + 1890*(g*x + f)^(3/2)*c*d*f^2*g^49*e^2 - 3780*sqrt(g*x + f)*c*d*f^3*g^49*e^2 + 315*(g*x + f)^(3/2)*a*d*g^5
1*e^2 - 1890*sqrt(g*x + f)*a*d*f*g^51*e^2 + 35*(g*x + f)^(9/2)*c*g^48*e^3 - 225*(g*x + f)^(7/2)*c*f*g^48*e^3 +
630*(g*x + f)^(5/2)*c*f^2*g^48*e^3 - 1050*(g*x + f)^(3/2)*c*f^3*g^48*e^3 + 1575*sqrt(g*x + f)*c*f^4*g^48*e^3
+ 63*(g*x + f)^(5/2)*a*g^50*e^3 - 315*(g*x + f)^(3/2)*a*f*g^50*e^3 + 945*sqrt(g*x + f)*a*f^2*g^50*e^3)/g^54